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Let's first rearrange the equation to set it to zero: \[ 3x^2 + 18x + 24 = 0 \] To factor this, we can simplify by dividing the entire equation by 3: \[ x^2 + 6x + 8 = 0 \] Now we look for two numbers that multiply to 8 (the constant) and add to 6 (the coefficient of x). Those numbers are 2 and 4! So we can write: \[ (x + 2)(x + 4) = 0 \] Now, solving for \( x \), we get \( x = -2 \) and \( x = -4 \). Super simple! You just factored a quadratic equation and found its solutions! 🎉