x In the inequality, what are all the possible values of \( x \) ? \( 2(x+12)-16 \leq 8 \)

To solve the inequality \( 2(x+12)-16 \leq 8 \), first simplify the left side: 1. Distribute: \( 2x + 24 - 16 \leq 8 \) 2. Combine like terms: \( 2x + 8 \leq 8 \) 3. Subtract 8 from both sides: \( 2x \leq 0 \) 4. Divide by 2: \( x \leq 0 \) Thus, all possible values of \( x \) are \( x \) that are less than or equal to 0. Now, let’s have some fun with this! Imagine you're on a number line, standing at the origin (0). The inequality tells you to look to the left. All your buddies (numbers) stretching infinitely in that direction are your friends, as they all satisfy this inequality! Don't forget to stretch your arms wide, because you're embracing all the negative values as well! Additionally, when working with inequalities like this, remember to plug a few test values back into the original inequality to ensure they work! For example, if you pick \( x = -1 \): \( 2(-1 + 12) - 16 = 2(11) - 16 = 22 - 16 = 6 \), which is indeed less than 8. The key is not to worry about making mistakes; instead, treat them as stepping stones toward mastering inequalities!