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\( 1 \leftarrow \underbrace{\left(2 a^{3}+4 b^{3}\right)-\left(4 a^{2} b-3 a b^{2}+4 b^{3}+2 a^{3}\right)} \begin{array}{l}\text { The difference is } \square . \text { (Simplify your answer.) } \\ \end{array} \)

Ask by Moreno Coleman. in the United States
Feb 17,2025

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Tutor-Verified Answer

Answer

The difference is \( ab(3b - 4a) \).

Solution

We start with the expression:   (2a³ + 4b³) - (4a²b - 3ab² + 4b³ + 2a³). Step 1: Distribute the minus sign to the second group:   2a³ + 4b³ - 4a²b + 3ab² - 4b³ - 2a³. Step 2: Combine like terms:   2a³ - 2a³ = 0,   4b³ - 4b³ = 0, leaving us with:   -4a²b + 3ab². Step 3: Factor out the common factor ab:   ab(-4a + 3b). Thus, the simplified expression is: ab(3b - 4a). The difference is ab(3b - 4a).

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Simplify this solution

The Deep Dive

To simplify the expression, we first need to combine all the terms: \[ (2a^3 + 4b^3) - (4a^2b - 3ab^2 + 4b^3 + 2a^3) \] Distributing the negative sign: \[ 2a^3 + 4b^3 - 4a^2b + 3ab^2 - 4b^3 - 2a^3 \] Now, we can combine the like terms. The \(2a^3\) and \(-2a^3\) cancel out, and the \(4b^3\) and \(-4b^3\) also cancel: \[ -4a^2b + 3ab^2 \] Thus, the simplified expression is: \[ 3ab^2 - 4a^2b \] So, the difference is \(3ab^2 - 4a^2b\).

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