20. The radiation emitted from the incandescent lamp is emitted at a temperature of 3000K. So, the ratio between the IR emitted to the total radiation energy of the incandescent lamp is....

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We need to find the ratio of infrared (IR) radiation emitted to the total radiation energy emitted by an incandescent lamp at a temperature of 3000K. This involves understanding the spectral distribution of blackbody radiation.
Planck's Law describes the spectral density of electromagnetic radiation emitted by a black body in thermal equilibrium at a given temperature. The total energy emitted can be calculated using the Stefan-Boltzmann Law, and the IR portion can be determined by integrating the Planck's Law over the IR range.
The total radiation energy emitted by a black body is given by the Stefan-Boltzmann Law: 
$$
E_{total} = \sigma T^4
$$
where $$ \sigma $$ is the Stefan-Boltzmann constant and $$ T $$ is the temperature in Kelvin.
The IR radiation can be approximated by integrating Planck's Law over the IR range (typically from 700 nm to 1 mm). However, for simplicity, we can use the approximation that about 50% of the total energy emitted by a black body at 3000K is in the IR range.
The ratio of IR emitted to total radiation energy can be approximated as:
$$
\text{Ratio} = \frac{E_{IR}}{E_{total}} \approx \frac{0.5 E_{total}}{E_{total}} = 0.5
$$
The ratio between the IR emitted to the total radiation energy of the incandescent lamp at 3000K is approximately $$ 0.5 $$ or 50%.

The radiation emitted from the incandescent lamp is emitted at a temperature of 3000K. So, the ratio between the IR emitted to the total radiation energy of the incandescent lamp is…

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