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4.1. \( 60-(-15)+(-13) \) 4.2. \( -2(-3)+27 \div(-3)+3 \) 4.3. \( -3 \times \sqrt[3]{-1}+49 \div(\sqrt{49}) \) 4.4. \( \sqrt{25}+\sqrt[3]{27}-2(-3)^{0} \)

Ask by Barnett Martinez. in South Africa
Feb 25,2025

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Tutor-Verified Answer

Answer

4.1 = 62 4.2 = 0 4.3 = 10 4.4 = 6

Solution

Let's evaluate each expression one by one. 4.1. 60 - (-15) + (-13)  • First, subtracting a negative is equivalent to adding a positive: 60 + 15 = 75.  • Then add -13: 75 + (-13) = 75 - 13 = 62. 4.2. -2(-3) + 27 ÷ (-3) + 3  • Multiply: -2 × (-3) = 6.  • Division: 27 ÷ (-3) = -9.  • Combine: 6 + (-9) + 3 = 0. 4.3. -3 × ∛(-1) + 49 ÷ (√49)  • The cube root of -1 is -1, so: -3 × (-1) = 3.  • The square root of 49 is 7, so: 49 ÷ 7 = 7.  • Combine: 3 + 7 = 10. 4.4. √25 + ∛27 - 2(-3)^0  • The square root of 25 is 5, and the cube root of 27 is 3.  • Any nonzero number to the zero power is 1: (-3)^0 = 1.  • Multiply: 2 × 1 = 2.  • Combine: 5 + 3 - 2 = 6. Final Answers: • 4.1 = 62 • 4.2 = 0 • 4.3 = 10 • 4.4 = 6

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The Deep Dive

Let's dive into these calculations in a fun and engaging way! For \( 60 - (-15) + (-13) \): When you subtract a negative, it's like adding a positive! So, we can rework it like this: \( 60 + 15 - 13 = 62 \). Next, for \( -2(-3) + 27 \div (-3) + 3 \): First, multiplying \( -2 \) and \( -3 \) gives us 6. \( 27 \div (-3) \) equals -9, so we have \( 6 - 9 + 3 \), which simplifies down to \( 0 \). Moving on to \( -3 \times \sqrt[3]{-1} + 49 \div (\sqrt{49}) \): The cube root of -1 is -1, so that makes \( -3 \times -1 = 3 \). The square root of 49 is 7, and \( 49 \div 7 = 7 \). So, we add \( 3 + 7 = 10 \). Finally, for \( \sqrt{25} + \sqrt[3]{27} - 2(-3)^0 \): The square root of 25 is 5, and the cube root of 27 is 3. \( (-3)^0 \) equals 1, so \( -2 \times 1 = -2 \). Now, we add \( 5 + 3 - 2 = 6 \). In summary, the answers are: 4.1. 62 4.2. 0 4.3. 10 4.4. 6

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