Question
A marine biologist measured one fish that was \( 3 / 4 \) of a foot long and a second fish that was \( 1 / 3 \) of a foot long. How much longer was the first fish? Write your answer as a fraction or as a whole or mixed number. feet
Ask by Garrett Wilson. in the United States
Feb 25,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
The first fish was \( \frac{5}{12} \) feet longer than the second fish.
Solution
To find how much longer the first fish was, subtract the length of the second fish from the first fish’s length:
3/4 − 1/3
First, find a common denominator (which is 12):
3/4 = 9/12
1/3 = 4/12
Now subtract:
9/12 − 4/12 = 5/12
So, the first fish was 5/12 feet longer than the second fish.
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Simplify this solution The Deep Dive
To find out how much longer the first fish was than the second, we need to subtract the length of the second fish from the length of the first fish. The first fish is \( \frac{3}{4} \) of a foot long and the second fish is \( \frac{1}{3} \) of a foot long. To perform this subtraction, we need a common denominator, which for 4 and 3 is 12. Rewriting the fractions: - \( \frac{3}{4} = \frac{3 \times 3}{4 \times 3} = \frac{9}{12} \) - \( \frac{1}{3} = \frac{1 \times 4}{3 \times 4} = \frac{4}{12} \) Now, subtract: \[ \frac{9}{12} - \frac{4}{12} = \frac{5}{12} \] So, the first fish is \( \frac{5}{12} \) of a foot longer than the second fish.
