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Given \( T(8,-2), U(-8,2), V(-9,5) \), and \( W(x, 4) \). Find \( x \) such that \( \overline{T U} \| \overline{V W} \). Answer Attempt 1 out of 2

Ask by Weber Fuentes. in the United States
Feb 20,2025

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Tutor-Verified Answer

Answer

\( x = -5 \)

Solution

To have TU parallel to VW, the segments must have equal slopes. Step 1: Find the slope of TU.   T(8, –2) and U(–8, 2):   Slope = (2 – (–2)) / (–8 – 8) = (4) / (–16) = –1/4 Step 2: Find the slope of VW.   V(–9, 5) and W(x, 4):   Slope = (4 – 5) / (x – (–9)) = (–1) / (x + 9) Step 3: Set the slopes equal.   –1/4 = –1/(x + 9) Remove the negative signs:   1/4 = 1/(x + 9) Solve for x by cross-multiplying:   x + 9 = 4   x = 4 – 9 = –5 Thus, the value of x for which segment TU is parallel to segment VW is –5.

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To find \( x \) such that \( \overline{T U} \| \overline{V W} \), we first need to determine the slopes of the lines \( \overline{TU} \) and \( \overline{VW} \). The slope of the line segment \( \overline{TU} \) between points \( T(8, -2) \) and \( U(-8, 2) \) is given by: \[ \text{slope of } \overline{TU} = \frac{y_2 - y_1}{x_2 - x_1} = \frac{2 - (-2)}{-8 - 8} = \frac{2 + 2}{-16} = \frac{4}{-16} = -\frac{1}{4} \] Next, we will find the slope of the line segment \( \overline{VW} \) between points \( V(-9, 5) \) and \( W(x, 4) \): \[ \text{slope of } \overline{VW} = \frac{4 - 5}{x - (-9)} = \frac{-1}{x + 9} \] Since \( \overline{TU} \) and \( \overline{VW} \) are parallel, their slopes must be equal: \[ -\frac{1}{4} = \frac{-1}{x + 9} \] To solve for \( x \), we cross-multiply: \[ -1 \cdot (x + 9) = -4 \cdot 1 \] This simplifies to: \[ -x - 9 = -4 \] Now, adding 9 to both sides gives us: \[ -x = 5 \quad \Rightarrow \quad x = -5 \] Thus, the value of \( x \) such that \( \overline{TU} \| \overline{VW} \) is \( \boxed{-5} \).

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