Let \( f \) be the function given by the formula \( f(x)=5-2 x \) on the domain \( D=\{x \mid x=2,3,4,5\} \). Make a table of the \( x \) of 1 and \( y \)-values to determine the range of f . Then, sketch the graph of t . The range of \( f \) is \( \{\square\} \). (Use a comma to separate answers as needed.)
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To determine the range of the function \( f(x) = 5 - 2x \) on the domain \( D = \{2, 3, 4, 5\} \), we can plug each value of \( x \) into the function to find the corresponding \( y \)-values. | \( x \) | \( f(x) \) | |:-----------:|:--------------:| | 2 | 1 | | 3 | -1 | | 4 | -3 | | 5 | -5 | Now, to list the \( y \)-values we found, the range of \( f \) is \( \{1, -1, -3, -5\} \). So, the range of \( f \) is \( \{1, -1, -3, -5\} \). For the sketch of the graph, you would plot the points (2, 1), (3, -1), (4, -3), and (5, -5), connecting them to visually represent the linear function \( f(x) = 5 - 2x \).