As the air rises, it will continue to cool at the WAR of 3.4 degrees F per \( 1,000 \mathrm{ft} \). What will the temperature within the cloud be above Shreveport, LA at \( 11,000 \mathrm{ft} \) ? 41 degrees F 14.6 degrees F 10.4 degrees F

To find the temperature within the cloud at \( 11,000 \mathrm{ft} \) above Shreveport, LA, we need to apply the given rate of cooling, which is \( 3.4 \) degrees F per \( 1,000 \mathrm{ft} \). ### Step 1: Calculate the total cooling First, we need to determine how many \( 1,000 \mathrm{ft} \) increments are in \( 11,000 \mathrm{ft} \): \[ \text{Number of increments} = \frac{11,000 \mathrm{ft}}{1,000 \mathrm{ft}} = 11 \] ### Step 2: Calculate the total temperature drop Next, we calculate the total temperature drop by multiplying the number of increments by the cooling rate: \[ \text{Total cooling} = 11 \times 3.4 \text{ degrees F} = 37.4 \text{ degrees F} \] ### Step 3: Determine the initial temperature To find the temperature within the cloud, we need to know the initial temperature at ground level (Shreveport, LA). However, since the initial temperature is not provided in the problem, we will assume it is one of the options given. Let's check each option to see if it makes sense when we apply the cooling. 1. **If the initial temperature is \( 41 \text{ degrees F} \)**: \[ \text{Temperature at } 11,000 \mathrm{ft} = 41 \text{ degrees F} - 37.4 \text{ degrees F} = 3.6 \text{ degrees F} \] 2. **If the initial temperature is \( 14.6 \text{ degrees F} \)**: \[ \text{Temperature at } 11,000 \mathrm{ft} = 14.6 \text{ degrees F} - 37.4 \text{ degrees F} = -22.8 \text{ degrees F} \] 3. **If the initial temperature is \( 10.4 \text{ degrees F} \)**: \[ \text{Temperature at } 11,000 \mathrm{ft} = 10.4 \text{ degrees F} - 37.4 \text{ degrees F} = -27.0 \text{ degrees F} \] ### Conclusion Since the initial temperature is not provided, we cannot definitively determine the temperature at \( 11,000 \mathrm{ft} \) without that information. However, if we assume the initial temperature is \( 41 \text{ degrees F} \), the temperature at \( 11,000 \mathrm{ft} \) would be \( 3.6 \text{ degrees F} \), which is not one of the options. If we consider the options given, none of them seem to be a reasonable initial temperature for Shreveport, LA, as they all lead to negative temperatures when applying the cooling rate. Please provide the initial temperature at ground level for a more accurate calculation.