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EXERCISE 1 1. Expand and simplify: \( \begin{array}{ll}\text { (a) } 2 x(x+2) & \text { (l) }(x+2)^{2}\end{array} \)

Ask by Evans Franklin. in South Africa
Feb 19,2025

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Answer

\( 2x(x + 2) = 2x^2 + 4x \) \( (x + 2)^2 = x^2 + 4x + 4 \)

Solution

Simplify the expression by following steps: - step0: Calculate: \(\left(x+2\right)^{2}\) - step1: Calculate: \(x^{2}+4x+4\) Expand the expression \( 2 x (x + 2) \) Simplify the expression by following steps: - step0: Multiply the terms: \(2x\left(x+2\right)\) - step1: Apply the distributive property: \(2x\times x+2x\times 2\) - step2: Multiply the terms: \(2x^{2}+4x\) Let's expand and simplify the given expressions step by step. ### (a) Expand \( 2x(x + 2) \) 1. Distribute \( 2x \) to both terms inside the parentheses: \[ 2x(x + 2) = 2x \cdot x + 2x \cdot 2 \] 2. This results in: \[ 2x^2 + 4x \] ### (l) Expand \( (x + 2)^{2} \) 1. Use the formula for the square of a binomial, \( (a + b)^2 = a^2 + 2ab + b^2 \): \[ (x + 2)^{2} = x^{2} + 2 \cdot x \cdot 2 + 2^{2} \] 2. This results in: \[ x^{2} + 4x + 4 \] ### Final Results - For \( 2x(x + 2) \): \( 2x^2 + 4x \) - For \( (x + 2)^{2} \): \( x^{2} + 4x + 4 \)

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The Deep Dive

To expand and simplify \(2x(x+2)\), you multiply \(2x\) by each term inside the parentheses: \(2x(x+2) = 2x^2 + 4x.\) Now, for \((x+2)^2\), you apply the formula for the square of a binomial: \((x+2)^2 = x^2 + 4x + 4.\) So your final simplified forms are: (a) \(2x^2 + 4x\) and (l) \(x^2 + 4x + 4.\)

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