Question

\( x^{2}-x y-6 y^{2}=6 \) and \( x+2 y=6 \)

Ask by Cook Owen. in South Africa
Feb 20,2025

Upstudy AI Solution

Tutor-Verified Answer

Answer

The solution is \( x=4 \) and \( y=1 \).

Solution

Solve the system of equations \( x^{2}-x y-6 y^{2}=6;x+2 y=6 \). Solve the system of equations by following steps: - step0: Solve using the substitution method: \(\left\{ \begin{array}{l}x^{2}-xy-6y^{2}=6\\x+2y=6\end{array}\right.\) - step1: Solve the equation: \(\left\{ \begin{array}{l}x^{2}-xy-6y^{2}=6\\x=6-2y\end{array}\right.\) - step2: Substitute the value of \(x:\) \(\left(6-2y\right)^{2}-\left(6-2y\right)y-6y^{2}=6\) - step3: Simplify: \(36-30y=6\) - step4: Move the constant to the right side: \(-30y=6-36\) - step5: Subtract the numbers: \(-30y=-30\) - step6: Change the signs: \(30y=30\) - step7: Divide both sides: \(\frac{30y}{30}=\frac{30}{30}\) - step8: Divide the numbers: \(y=1\) - step9: Substitute the value of \(y:\) \(x=6-2\times 1\) - step10: Substitute back: \(x=6-2\) - step11: Calculate: \(x=4\) - step12: Calculate: \(\left\{ \begin{array}{l}x=4\\y=1\end{array}\right.\) - step13: Check the solution: \(\left\{ \begin{array}{l}x=4\\y=1\end{array}\right.\) - step14: Rewrite: \(\left(x,y\right) = \left(4,1\right)\) The solution to the system of equations is \( (x,y) = (4,1) \).

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Mind Expander

Alright, let's dive into these equations! The first one, \( x^{2}-xy-6y^{2}=6 \), describes a conic section, while the second one, \( x+2y=6 \), is a linear equation representing a straight line. To solve this system, you can substitute the expression for \( x \) from the linear equation into the quadratic equation. Then, you’ll be able to find values for \( y \) and subsequently for \( x \). Once you substitute \( x = 6 - 2y \) into the first equation, you can solve for \( y \) and find the solutions to this pair of equations. Just watch out for any potential algebraic missteps when expanding and rearranging the terms! Have fun solving!

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