State the vertex of the function, $$ g(x)=(x+2)^{2}-1 $$ $$ (2,1) $$ $$ (-2,-1) $$ $$ (-2,1) $$ $$ (-2,-1) $$

Question

UpStudy AI · Accepted Answer

The function is given in vertex form,

$$
g(x) = (x+2)^2 - 1.
$$

In a vertex form, $$ g(x) = (x - h)^2 + k $$, the vertex is at the point $$(h, k)$$.

Comparing

$$
(x+2)^2 = (x - (-2))^2,
$$

with $$ (x - h)^2 $$, we have $$ h = -2 $$.

The constant term is $$ k = -1 $$.

Thus, the vertex is

$$
(-2, -1).
$$
The vertex of the function $$ g(x) = (x+2)^2 - 1 $$ is at $$(-2, -1)$$.

State the vertex of the function, \( g(x)=(x+2)^{2}-1 \) \( (2,1) \) \( (-2,-1) \) \( (-2,1) \) \( (-2,-1) \)