Find the \( 56^{\text {th }} \) term of the following arithmetic sequence. \[ 4,11,18,25, \ldots \]

To find the \( 56^{\text{th}} \) term of the arithmetic sequence \( 4, 11, 18, 25, \ldots \), we first need to identify the first term and the common difference. The first term \( a \) is \( 4 \) and the common difference \( d \) can be determined by subtracting the first term from the second term: \[ d = 11 - 4 = 7. \] The formula for the \( n^{\text{th}} \) term of an arithmetic sequence is given by: \[ a_n = a + (n-1) \cdot d. \] Now, substituting \( a = 4 \), \( d = 7 \), and \( n = 56 \) into the formula: \[ a_{56} = 4 + (56 - 1) \cdot 7. \] Calculating \( (56 - 1) \cdot 7 \): \[ 55 \cdot 7 = 385. \] Now, substituting this value back into the formula: \[ a_{56} = 4 + 385 = 389. \] Thus, the \( 56^{\text{th}} \) term of the sequence is \(\boxed{389}\).