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If rwo-thord of a number is 60 , what is one-xixth of that same number? 4. 78 A. बa C. 48 1. 30 E. 15 Thetre.F of two mumbers is 3 . Which of the followiag pairs represcents the foo numbers in the oprotas below? A. 12 and 17 B. 10 and 20 C 9 and 15 n 8 and 12 E 4 and 6 35: ef watlutor is less than one of the following by \( \mathrm{N} \$ 0.00 \). A. P 195.00 B. N205.00 C. anens.00 D. N230.00 E. स240.00 Chinge \( \$ 432.08 \) to kobo. A. 320 B. 328 C \( \quad 330 \) D. 3208 E 3,280 How many \( \$ 2.0 .00 \) added up to make N1.000.00? A. 10 B. 50 C. 100 D. 110 E \( \quad 1,000 \) 14. Change \( 7 \frac{1}{2} \), 6 to fraction in ita lerwest A. \( \frac{1}{2} \) B. \( \frac{1}{20} \) C. \( \frac{1}{20} \) D. \( \frac{3}{40} \) E. \( \frac{3}{40} \) 15. Conven 8 weeks 8 days to days. A. 64 B. 56 C. \( \quad 48 \) D. 39 E. \( \quad 28 \) 16. The marked price of an article is \( \$ 8,200.00 \). If a customer receives \( \$ 410.00 \) as a discount on the article. what percentage is the discount? A. 4 B. 5 C. 6 D. 8 E. 10 17. Subtract 8 cm 7 mm from 42 cm 5 cmm . A. 34 cm 8 mm B. 34 cm 13 mm C. \( \quad 33 \mathrm{~cm} 98 \mathrm{~mm} \) D. 33 cm 8 mm B. 32 cm 15 mm

Ask by Rodriguez Morgan. in Nigeria
Feb 20,2025

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Answer

**Simplified Answers:** 1. **Problem 1:** 15 (Option E) 2. **Problem 2:** None of the options sum to 3. 3. **Problem 3:** 43208 kobo (Not listed) 4. **Problem 4:** 500 (Not listed) 5. **Problem 5:** 15⁄2 (Not listed) 6. **Problem 6:** 64 days (Option A) 7. **Problem 7:** 5% (Option B) 8. **Problem 8:** 33 cm 8 mm (Option D)

Solution

Let's solve the problems step by step. ### Problem 1: If two-thirds of a number is 60, what is one-sixth of that same number? 1. Let the number be \( x \). 2. According to the problem, we have: \[ \frac{2}{3}x = 60 \] 3. To find \( x \), we can multiply both sides by \( \frac{3}{2} \): \[ x = 60 \times \frac{3}{2} = 90 \] 4. Now, we need to find one-sixth of \( x \): \[ \frac{1}{6}x = \frac{1}{6} \times 90 = 15 \] **Final Answer for Problem 1: 15 (Option E)** --- ### Problem 2: The sum of two numbers is 3. Which of the following pairs represents the two numbers? 1. Let the two numbers be \( a \) and \( b \). 2. We have: \[ a + b = 3 \] 3. Now, we will check each option to see if the sum equals 3. - **Option A: 12 and 17** \[ 12 + 17 = 29 \quad (\text{Not valid}) \] - **Option B: 10 and 20** \[ 10 + 20 = 30 \quad (\text{Not valid}) \] - **Option C: 9 and 15** \[ 9 + 15 = 24 \quad (\text{Not valid}) \] - **Option D: 8 and 12** \[ 8 + 12 = 20 \quad (\text{Not valid}) \] - **Option E: 4 and 6** \[ 4 + 6 = 10 \quad (\text{Not valid}) \] None of the options provided sum to 3. --- ### Problem 3: Change \( \$ 432.08 \) to kobo. 1. Since \( 1 \) dollar is equal to \( 100 \) kobo, we can convert: \[ 432.08 \times 100 = 43208 \text{ kobo} \] **Final Answer for Problem 3: 43208 (Not listed in options)** --- ### Problem 4: How many \( \$ 2.00 \) added up to make \( N1,000.00 \)? 1. Let \( n \) be the number of \( \$ 2.00 \): \[ 2n = 1000 \] 2. Solving for \( n \): \[ n = \frac{1000}{2} = 500 \] **Final Answer for Problem 4: 500 (Not listed in options)** --- ### Problem 5: Change \( 7 \frac{1}{2} \) to a fraction in its lowest terms. 1. Convert \( 7 \frac{1}{2} \) to an improper fraction: \[ 7 \frac{1}{2} = \frac{15}{2} \] **Final Answer for Problem 5: \( \frac{15}{2} \) (Not listed in options)** --- ### Problem 6: Convert 8 weeks 8 days to days. 1. There are \( 7 \) days in a week, so: \[ 8 \text{ weeks} = 8 \times 7 = 56 \text{ days} \] 2. Adding the extra days: \[ 56 + 8 = 64 \text{ days} \] **Final Answer for Problem 6: 64 (Option A)** --- ### Problem 7: The marked price of an article is \( \$ 8,200.00 \). If a customer receives \( \$ 410.00 \) as a discount, what percentage is the discount? 1. The discount percentage can be calculated as: \[ \text{Discount Percentage} = \left( \frac{410}{8200} \right) \times 100 \] 2. Calculating: \[ \text{Discount Percentage} = \left( \frac{410}{8200} \right) \times 100 = 5 \] **Final Answer for Problem 7: 5% (Option B)** --- ### Problem 8: Subtract \( 8 \text{ cm } 7 \text{ mm} \) from \( 42 \text{ cm } 5 \text{ mm} \). 1. Convert everything to mm: - \( 42 \text{ cm } 5 \text{ mm} = 420 + 5 = 425 \text{ mm} \) - \( 8 \text{ cm } 7 \text{ mm} = 80 + 7 = 87 \text{ mm} \) 2. Now subtract: \[ 425 - 87 = 338 \text{ mm} \] 3. Convert back to cm and mm: - \( 338 \text{ mm} = 33 \text{ cm } 8 \text{ mm} \) **Final Answer for Problem 8: 33 cm 8 mm (Option D)** --- If you have any further questions or need additional assistance, feel free to ask!

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Bonus Knowledge

To find one-sixth of the same number from the information that two-thirds of the number is 60, first determine the entire number. If two-thirds is 60, then the entire number is 60 multiplied by \(\frac{3}{2}\), which equals 90. Subsequently, one-sixth of 90 is 15. Voila! For the second problem regarding which pairs of numbers have a threefold proportion, it's essential to recognize that the relationship dictates that the ratio of the two numbers must simplify to 1:3. A pair like (4 and 6) does not fulfill the condition of being in the specified ratio. However, exploring the correct options reveals that pairs like (9 and 15) meet the requirement perfectly, yielding a ratio of 1:5, while (10 and 20) offers a neat 1:2 equivalence. Fun with numbers, right?

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