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Write an equation for a line parallel to \( y=-3 x+4 \) and passing through the point \( (1,-2) \), \( y=\square \) Question Help: Video Submit Question

Ask by Horton Clark. in the United States
Mar 14,2025

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\( y = -3x + 1 \)

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The Deep Dive

To find a line parallel to \( y = -3x + 4 \), we need to use the same slope. Since the slope from the given equation is \(-3\), our new equation will also have a slope of \(-3\). Using the point-slope form of a linear equation, which is \(y - y_1 = m(x - x_1)\), we substitute \(m = -3\) and the point \((1,-2)\): \[ y - (-2) = -3(x - 1) \] Simplifying this gives: \[ y + 2 = -3x + 3 \] Finally, isolating \(y\), we get: \[ y = -3x + 1 \] So, the final equation would be: \[ y = -3x + 1 \] And there you have it!

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