Express as a single fraction \( \frac{1}{x+1}+\frac{4}{x-2} \)
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Bonus Knowledge
To combine the fractions \( \frac{1}{x+1}+\frac{4}{x-2} \) into a single fraction, we first need a common denominator. The common denominator is \((x+1)(x-2)\). Now, we can rewrite each fraction with the common denominator: \[ \frac{1}{x+1} = \frac{1(x-2)}{(x+1)(x-2)} = \frac{x-2}{(x+1)(x-2)} \] \[ \frac{4}{x-2} = \frac{4(x+1)}{(x-2)(x+1)} = \frac{4x + 4}{(x+1)(x-2)} \] Now we can add them together: \[ \frac{x-2}{(x+1)(x-2)} + \frac{4x + 4}{(x+1)(x-2)} = \frac{x - 2 + 4x + 4}{(x+1)(x-2)} = \frac{5x + 2}{(x+1)(x-2)} \] So the expression \( \frac{1}{x+1}+\frac{4}{x-2} \) as a single fraction is: \[ \frac{5x + 2}{(x+1)(x-2)} \]