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Write the exponential model given two point 1) \( (9,140) \) and \( (10,250) \)

Ask by Thornton Dickson. in the United States
Feb 11,2025

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Answer

The exponential model based on the points (9,140) and (10,250) is: y = 140 · (25/14)^(x – 9).

Solution

We start with an exponential model of the form   y = A · B^(x – x₀) where x₀ is the x-coordinate of one of the given points. It’s often convenient to choose the smaller x-value. Here, let x₀ = 9 and A = 140, so the model becomes   y = 140 · B^(x – 9). Now, use the second point (10, 250) to find B:   250 = 140 · B^(10 – 9) = 140 · B. Solve for B:   B = 250/140 = 25/14. Thus, the exponential model is   y = 140 · (25/14)^(x – 9). An alternative form using the natural exponential is to note that B = e^k, where   k = ln(25/14), so the model can also be written as   y = 140 · e^(ln(25/14)·(x – 9)). Both forms describe the same exponential model based on the two given points.

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Bonus Knowledge

To build the exponential model based on your points, we can express it in the form \( y = a \cdot b^x \). Starting with the two points: 1. From \( (9, 140) \): \( 140 = a \cdot b^9 \) 2. From \( (10, 250) \): \( 250 = a \cdot b^{10} \) Now, dividing the second equation by the first gives us: \[ \frac{250}{140} = \frac{a \cdot b^{10}}{a \cdot b^{9}} \] This simplifies to: \[ \frac{25}{14} = b \rightarrow b \approx 1.7857 \] Now plug \( b \) back into one of the equations to find \( a \): \[ 140 = a \cdot (1.7857)^9 \] \[ a \approx \frac{140}{(1.7857)^9} \approx 22.56 \] Thus, the exponential model is: \[ y \approx 22.56 \cdot (1.7857)^x \] Now you have a vibrant model to predict values beyond your original data points!

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