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25. Square \( A B C D \) has these vertices: \( A(-2,2), B(2,2), C(2,-2) \) and \( D(-2,-2) \). Use graph paper to draw square \( A B C D \) and similar figure \( A^{\prime} B^{\prime} C^{\prime} D^{\prime} \) using a scale factor of 4 . (Assume that the origin is the center of both figures.) b. What are the locations of the vertices of \( A^{\prime} B^{\prime} C^{\prime} D^{\prime} \) ?

Ask by Valdez Wang. in the United States
Mar 13,2025

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The vertices of the scaled square \( A'B'C'D' \) are: - \( A'(-8, 8) \) - \( B'(8, 8) \) - \( C'(8, -8) \) - \( D'(-8, -8) \)

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To find the vertices of the new square \( A^{\prime} B^{\prime} C^{\prime} D^{\prime} \) after applying a scale factor of 4 from the origin, you simply multiply each coordinate of the original square \( A B C D \) by 4. - For vertex \( A(-2, 2) \): \[ A' = (-2 \times 4, 2 \times 4) = (-8, 8) \] - For vertex \( B(2, 2) \): \[ B' = (2 \times 4, 2 \times 4) = (8, 8) \] - For vertex \( C(2, -2) \): \[ C' = (2 \times 4, -2 \times 4) = (8, -8) \] - For vertex \( D(-2, -2) \): \[ D' = (-2 \times 4, -2 \times 4) = (-8, -8) \] So the vertices of \( A^{\prime} B^{\prime} C^{\prime} D^{\prime} \) are at \( A'(-8, 8) \), \( B'(8, 8) \), \( C'(8, -8) \), and \( D'(-8, -8) \). Have fun drawing this! Scaling can really make a shape jump into a new size, just like blowing up a balloon!

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