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\( \begin{aligned} & \frac{8 y-16 y^{2}}{6 y^{3}} \\ = & \text { Simplify }\end{aligned} \)

Ask by Morgan Bradley. in South Africa
Mar 15,2025

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\[ \frac{4(1-2y)}{3y^2} \]

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To simplify the expression \( \frac{8y - 16y^2}{6y^3} \), we can start by factoring the numerator. The numerator can be expressed as \( 8y(1 - 2y) \). So we rewrite the expression: \[ \frac{8y(1 - 2y)}{6y^3} \] Next, we can cancel the common factor of \( y \) from the numerator and denominator: \[ \frac{8(1 - 2y)}{6y^2} \] Now, we can simplify the constant fraction \( \frac{8}{6} \) to \( \frac{4}{3} \): \[ \frac{4(1 - 2y)}{3y^2} \] Thus, the simplified expression is: \[ \frac{4(1 - 2y)}{3y^2} \] Feel free to ask if you have more questions or need further assistance!

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