Make $$ b $$ the subject of the following formula: $$ a=\frac{14+2 b}{c} $$

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Solve the equation by following steps:
- step0: Solve for $$b$$:
  $$ac=14+2b$$
- step1: Swap the sides:
  $$14+2b=ac$$
- step2: Move the constant to the right side:
  $$2b=ac-14$$
- step3: Divide both sides:
  $$\frac{2b}{2}=\frac{ac-14}{2}$$
- step4: Divide the numbers:
  $$b=\frac{ac-14}{2}$$
Solve the equation $$ a=c(14+2b) $$.
Solve the equation by following steps:
- step0: Solve for $$b$$:
  $$a=c\left(14+2b\right)$$
- step1: Swap the sides:
  $$c\left(14+2b\right)=a$$
- step2: Divide both sides:
  $$\frac{c\left(14+2b\right)}{c}=\frac{a}{c}$$
- step3: Divide the numbers:
  $$14+2b=\frac{a}{c}$$
- step4: Move the constant to the right side:
  $$2b=\frac{a}{c}-14$$
- step5: Subtract the terms:
  $$2b=\frac{a-14c}{c}$$
- step6: Multiply by the reciprocal:
  $$2b\times \frac{1}{2}=\frac{a-14c}{c}\times \frac{1}{2}$$
- step7: Multiply:
  $$b=\frac{a-14c}{2c}$$
To make $$ b $$ the subject of the formula $$ a = \frac{14 + 2b}{c} $$, we can follow these steps:

1. **Multiply both sides by $$ c $$** to eliminate the fraction:
   $$
   ac = 14 + 2b
   $$

2. **Rearrange the equation** to isolate $$ 2b $$:
   $$
   2b = ac - 14
   $$

3. **Divide by 2** to solve for $$ b $$:
   $$
   b = \frac{ac - 14}{2}
   $$

Alternatively, we can express $$ b $$ in another form:

1. From the original equation, we can also rearrange it as:
   $$
   a = \frac{14 + 2b}{c} \implies ac = 14 + 2b
   $$

2. Rearranging gives:
   $$
   2b = ac - 14
   $$

3. Dividing by 2 results in:
   $$
   b = \frac{ac - 14}{2}
   $$

Thus, the final expression for $$ b $$ is:
$$
b = \frac{ac - 14}{2}
$$

This shows that $$ b $$ can be expressed in terms of $$ a $$ and $$ c $$.
$$ b = \frac{ac - 14}{2} $$

Make \( b \) the subject of the following formula: \[ a=\frac{14+2 b}{c} \]

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