A rectangular garden measures 20 ft by 37 ft Surrounding (end bordering) the garden is a path 2 f wide. Find the area of this path. Be sure to incuide the correct unit in your answer.

**Step 1: Determine the dimensions of the outer rectangle (garden + path).** The garden has dimensions \(20 \text{ ft}\) by \(37 \text{ ft}\). Since the path is \(2 \text{ ft}\) wide on every side, the length and width of the outer rectangle are increased by \(2 \times 2 = 4 \text{ ft}\) each. \[ \text{New width} = 20 + 4 = 24 \text{ ft} \] \[ \text{New length} = 37 + 4 = 41 \text{ ft} \] **Step 2: Calculate the area of the outer rectangle.** \[ \text{Area}_{\text{outer}} = 24 \times 41 = 984 \text{ ft}^2 \] **Step 3: Calculate the area of the garden (inner rectangle).** \[ \text{Area}_{\text{garden}} = 20 \times 37 = 740 \text{ ft}^2 \] **Step 4: Find the area of the path by subtracting the area of the garden from the area of the outer rectangle.** \[ \text{Area}_{\text{path}} = \text{Area}_{\text{outer}} - \text{Area}_{\text{garden}} = 984 - 740 = 244 \text{ ft}^2 \] **Final Answer:** The area of the path is \(244 \text{ ft}^2\).