3.2 Divide R 6500 in the ratio of \( 3: 4: 6 \). 3.3 . Mamatela wants to buy pears. 15 pears cost R15,60. How much will 27 of the same pears cost? 3.4 Seven men build a house in 300 days. How many men, working at the same rate, can build the house in 70 days?

### 3.2 Divide R 6500 in the ratio \( 3:4:6 \) 1. **Step 1: Find the sum of the parts.** \[ 3 + 4 + 6 = 13 \] 2. **Step 2: Calculate the value of one part.** \[ \text{One part} = \frac{6500}{13} = 500 \] 3. **Step 3: Multiply each ratio number by the value of one part.** - For the first part: \[ 3 \times 500 = 1500 \] - For the second part: \[ 4 \times 500 = 2000 \] - For the third part: \[ 6 \times 500 = 3000 \] 4. **Answer:** The amounts are R1500, R2000, and R3000 respectively. --- ### 3.3 Cost of 27 Pears 1. **Step 1: Find the cost of one pear.** \[ \text{Cost per pear} = \frac{15.60}{15} = 1.04 \text{ R} \] 2. **Step 2: Multiply the cost per pear by 27.** \[ 27 \times 1.04 = 28.08 \text{ R} \] 3. **Answer:** 27 pears will cost R28.08. --- ### 3.4 Building a House in 70 Days 1. **Step 1: Calculate the total work in man-days.** \[ \text{Total work} = 7 \text{ men} \times 300 \text{ days} = 2100 \text{ man-days} \] 2. **Step 2: Let \( x \) be the number of men needed to build the house in 70 days.** The work done by \( x \) men in 70 days must equal 2100 man-days: \[ x \times 70 = 2100 \] 3. **Step 3: Solve for \( x \).** \[ x = \frac{2100}{70} = 30 \] 4. **Answer:** 30 men are needed to build the house in 70 days.