Question
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1. \( 3 a^{2} b \times-2 a b^{3} \)

Ask by Nguyen Hamilton. in South Africa
Mar 11,2025

Upstudy AI Solution

Tutor-Verified Answer

Answer

\(-6a^3b^4\)

Solution

1. Multiply the numerical coefficients: \[ 3 \times (-2) = -6. \] 2. Multiply the \( a \) terms by adding the exponents: \[ a^2 \times a = a^{2+1} = a^3. \] 3. Multiply the \( b \) terms by adding the exponents: \[ b \times b^3 = b^{1+3} = b^4. \] 4. Combine the results: \[ 3 a^2 b \times (-2 a b^3) = -6 a^3 b^4. \]

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Simplify this solution

The Deep Dive

To simplify the expression \( 3 a^{2} b \times -2 a b^{3} \), you start by multiplying the coefficients and then combine the variables using the laws of exponents. First, multiply \(3\) and \(-2\) to get \(-6\). Then, for the variable \(a\), you have \(a^{2} \times a\), which equals \(a^{3}\) when you add the exponents. For \(b\), you have \(b \times b^{3}\), which equals \(b^{4}\). Putting it all together, the simplified expression is \(-6 a^{3} b^{4}\). Keep practicing with different coefficients and variable combinations, and soon you'll feel like a math magician, conjuring up neat solutions in no time! Just remember to keep track of your positive and negative signs—like magic, they can change the whole outcome!

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