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d) \( f(x)=-\frac{1}{4}(x+1)^{2}+5 \)

Ask by Erickson Rodriquez. in Canada
Feb 21,2025

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The function \( f(x) = -\frac{1}{4}(x+1)^{2} + 5 \) is a downward-opening parabola with its vertex at \( (-1, 5) \). It has an axis of symmetry at \( x = -1 \), a y-intercept at \( \left(0, \frac{19}{4}\right) \), and x-intercepts at \( x = -1 + 2\sqrt{5} \) and \( x = -1 - 2\sqrt{5} \).

Solution

To analyze the function \( f(x) = -\frac{1}{4}(x+1)^{2} + 5 \), we can identify several features of the function, such as its vertex, axis of symmetry, and whether it opens upwards or downwards. 1. **Identify the vertex**: The function is in vertex form \( f(x) = a(x-h)^{2} + k \), where \( (h, k) \) is the vertex. Here, \( a = -\frac{1}{4} \), \( h = -1 \), and \( k = 5 \). Thus, the vertex is at the point \( (-1, 5) \). 2. **Determine the direction of opening**: Since \( a < 0 \) (specifically, \( a = -\frac{1}{4} \)), the parabola opens downwards. 3. **Find the axis of symmetry**: The axis of symmetry is the vertical line that passes through the vertex, given by \( x = h \). Therefore, the axis of symmetry is \( x = -1 \). 4. **Calculate the y-intercept**: To find the y-intercept, we set \( x = 0 \): \[ f(0) = -\frac{1}{4}(0+1)^{2} + 5 = -\frac{1}{4}(1) + 5 = -\frac{1}{4} + 5 = \frac{19}{4} \] Thus, the y-intercept is \( \left(0, \frac{19}{4}\right) \). 5. **Find the x-intercepts**: To find the x-intercepts, we set \( f(x) = 0 \): \[ 0 = -\frac{1}{4}(x+1)^{2} + 5 \] Rearranging gives: \[ \frac{1}{4}(x+1)^{2} = 5 \] Multiplying both sides by 4: \[ (x+1)^{2} = 20 \] Taking the square root of both sides: \[ x + 1 = \pm \sqrt{20} \] Thus: \[ x = -1 \pm 2\sqrt{5} \] Therefore, the x-intercepts are \( x = -1 + 2\sqrt{5} \) and \( x = -1 - 2\sqrt{5} \). Now, let's summarize the findings: - Vertex: \( (-1, 5) \) - Opens: Downwards - Axis of symmetry: \( x = -1 \) - Y-intercept: \( \left(0, \frac{19}{4}\right) \) - X-intercepts: \( x = -1 + 2\sqrt{5} \) and \( x = -1 - 2\sqrt{5} \) If you need further analysis or specific calculations, please let me know!

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The Deep Dive

This function represents a parabola that opens downward, with its vertex at the point \((-1, 5)\). The negative coefficient of \(-\frac{1}{4}\) indicates that the parabola will have a "smaller" width compared to a standard parabola \(y = -x^2\), giving it a more pronounced peak. This feature means it achieves its maximum value of 5 at the vertex, and as \(x\) moves away from -1 in either direction, the function's value drops. One common mistake when working with parabolas is overlooking the vertex and its role in maximizing or minimizing the function. Always remember that the vertex represents the highest or lowest point in your parabolic graph, depending on whether it opens up or down. Additionally, confirming the direction (upward or downward) through the coefficient in front of the squared term is vital for accurately sketching its graph.

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