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The propulation of ine municdpality was 1792861 in 1996 , which was an Incesaes by \( 2,96 \% / \) from 1995 io 1996 , Determine the population of the munivipaligy in 1995 .

Ask by Moran May. in South Africa
Feb 25,2025

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Answer

The population in 1995 was approximately 1,741,318.

Solution

Let x be the population in 1995. According to the problem, the 1996 population is a 2.96% increase over the 1995 population. This means:   1996 population = x + 0.0296·x = 1.0296·x We are given that the 1996 population is 1,792,861. Therefore:   1.0296 · x = 1,792,861 To find x, divide both sides of the equation by 1.0296:   x = 1,792,861 / 1.0296 Now, performing the division:   x ≈ 1,741,317.7 Rounding to the nearest whole number, the population in 1995 was approximately 1,741,318.

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Bonus Knowledge

To find the population of the municipality in 1995, you can use the formula for percentage increase. Given a 2.96% increase from 1995 to 1996, you can express this as: Population in 1996 = Population in 1995 × (1 + percentage increase) This translates to: 1,792,861 = Population in 1995 × (1 + 0.0296) So, Population in 1995 = 1,792,861 / 1.0296 ≈ 1,739,301. The population of the municipality in 1995 was approximately 1,739,301. --- Did you know that population calculations like this have been key in urban planning? By understanding demographics, city planners can better allocate resources, design infrastructure, and anticipate future community needs—leading to great developments over time! Additionally, it's essential to double-check your calculations. A common mistake is misplacing the decimal or misunderstanding the percentage. Always double-verify by plugging your results back into the original percentage increase formula. It’s a simple step that can save a lot of headaches!

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