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7. Si le restamos \( (6 a+5 b) \), a la suma de \( (2 a+9 b) \) con \( (3 a-2 b) \), el resultado será: (A) \( 5 a+7 b \) (B) \( a+2 b \) (C) \( 2 b-a \) (D) \( b-2 a \) (E) \( 2 a+b \)

Ask by Cruz Haynes. in Chile
Nov 02,2024

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O resultado final é \( 2b - a \).

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Primero, sumemos \( (2 a + 9 b) \) y \( (3 a - 2 b) \): \[ (2 a + 9 b) + (3 a - 2 b) = 2 a + 3 a + 9 b - 2 b = 5 a + 7 b. \] Luego, restemos \( (6 a + 5 b) \) del resultado: \[ (5 a + 7 b) - (6 a + 5 b) = 5 a - 6 a + 7 b - 5 b = -a + 2 b = 2 b - a. \] Por lo tanto, el resultado final es la opción (C) \( 2 b - a \).

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