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Describe step by step transformations of the function: \[ f(x)=-2|\ln (x)+1|+1 \]

Ask by Harper Pena. in South Africa
Mar 09,2025

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The function \( f(x) = -2|\ln(x) + 1| + 1 \) is created by: 1. Starting with \( y = \ln(x) \), 2. Shifting it up by 1, 3. Taking the absolute value, 4. Stretching vertically by 2 and reflecting over the x-axis, 5. Finally, shifting up by 1.

Solution

1. **Start with the base function.** Consider the base function \[ y = \ln(x) \] which is defined for \( x > 0 \). 2. **Vertical translation upward by 1.** Add 1 to the output of the logarithm: \[ y = \ln(x) + 1. \] This shifts the graph of \( \ln(x) \) upward by 1 unit. 3. **Apply the absolute value.** Take the absolute value of the entire expression: \[ y = \left|\ln(x)+1\right|. \] This transformation reflects any portion of the graph that falls below the \( x \)-axis (i.e., where \( \ln(x)+1 < 0 \)) upward so that all output values become nonnegative. 4. **Vertical reflection and stretch.** Multiply the absolute value by \(-2\): \[ y = -2\left|\ln(x)+1\right|. \] - The factor \( 2 \) vertically stretches the graph by doubling the distance of each point from the \( x \)-axis. - The negative sign reflects the graph about the \( x \)-axis, turning the previously nonnegative outputs into nonpositive values. 5. **Final vertical translation upward by 1.** Add 1 to the result: \[ y = -2\left|\ln(x)+1\right| + 1. \] This final transformation shifts the entire graph upward by 1 unit. Thus, the function \[ f(x) = -2\left|\ln(x)+1\right| + 1 \] is obtained by performing the following sequence of transformations: - Start with \( y = \ln(x) \), - Shift upward by 1 to get \( y = \ln(x)+1 \), - Apply the absolute value to get \( y = \left|\ln(x)+1\right| \), - Vertically stretch by a factor of 2 and reflect about the \( x \)-axis to get \( y = -2\left|\ln(x)+1\right| \), - Finally, shift upward by 1 to obtain \( y = -2\left|\ln(x)+1\right|+1 \).

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First off, let’s break down our function step by step! We start with the natural logarithm function \( \ln(x) \), which is defined for \( x > 0 \). As we take \( \ln(x) \), it goes from negative infinity to positive infinity as \( x \) ranges from 0 to \( \infty \). Now, move on to the transformation! First, adding 1 inside the absolute value, we have \( |\ln(x) + 1| \). This shifts the graph left by \( e^{-1} \) on our natural log curve. Next, multiplying by -2 flips the graph vertically and stretches it vertically, making it concave down. After that, we add 1 at the end, which shifts the entire graph up by 1 unit. So our function not only reflects, but also “bobs” up, creating a fabulous new dance on the Cartesian plane! All these transformations go hand in hand to create an interesting graph. It starts below the horizontal line \( y = 1 \) for values of \( \ln(x) + 1 < 0 \) and peaks as \( |\ln(x) + 1| \) becomes large, creating intriguing local maxima depending on your input \( x \). Don't forget that it only exists for positive values of \( x \); beyond that, it's like trying to enter a party without an invitation!

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