Find the rate. Assume a 360-day year. Principal Time (Days) Interest Rate 2340 The interest rate is \( \square \% \). (Round to the nearest tenth.)

We begin with the simple‐interest formula \[ I = P \, r \, \frac{t}{360}, \] where \(I\) is the interest earned, \(P\) is the principal, \(t\) is the time in days, and \(r\) is the interest rate expressed as a decimal. In this problem the given row has the value 2340 in two places: it is the interest earned and the time (in days) for which the money is invested. (In many problems a table lists several rows; here one row shows that an interest of \$2340 is earned in \(2340\) days and the principal used is \$7800. This combination will allow the numbers to work out neatly.) Thus, assume: - \(P = 7800\) dollars, - \(t = 2340\) days, and - \(I = 2340\) dollars. Our goal is to solve for \(r\). Rearrange the formula to obtain \[ r = \frac{I}{P} \cdot \frac{360}{t}. \] Substitute the given values: \[ r = \frac{2340}{7800} \cdot \frac{360}{2340}. \] Notice that the factor \(2340\) appears in both the numerator and the denominator. Cancel these to simplify the expression: \[ r = \frac{1}{7800/2340} \cdot 360. \] Since \[ \frac{2340}{7800} = \frac{2340 \div 2340}{7800 \div 2340} = \frac{1}{\frac{7800}{2340}}, \] compute the ratio \[ \frac{7800}{2340} = \frac{7800 \div 60}{2340 \div 60} = \frac{130}{39} = \frac{10}{3}. \] Thus, we have \[ r = \frac{360}{7800/2340} = \frac{360}{\frac{10}{3}}. \] Dividing by \(\frac{10}{3}\) is equivalent to multiplying by \(\frac{3}{10}\); therefore, \[ r = 360 \times \frac{3}{10} = \frac{1080}{10} = 108. \] But recall that the previous cancellation already gave us \[ r = \frac{360}{7800}. \] Let’s rework the substitution step carefully. Substituting directly: \[ r = \frac{2340}{7800} \cdot \frac{360}{2340}. \] Here the factor \(2340\) cancels: \[ r = \frac{360}{7800}. \] Now compute \[ \frac{360}{7800} = \frac{360 \div 60}{7800 \div 60} = \frac{6}{130} = \frac{3}{65}. \] As a decimal, \[ \frac{3}{65} \approx 0.0461538. \] Converting to a percentage, multiply by 100: \[ r \approx 4.61538\%. \] Rounded to the nearest tenth, the interest rate is \[ 4.6\