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14) \( 4 x^{2}+13 x+3 \) 16) \( 4 x^{2}+\pi-3 \) 181 \( 3 x^{2}-4 x-4 \) 20) \( 2 x^{2}-5 x-3 \) 22) \( 7 a^{2}-11 a+4 \) 24) \( 24 x^{2}-30 a+9 \) 26) \( 2 x^{3} y+12 x^{2} y+18 x y \) 28) \( 2 x^{2}+8 x+6 \) 30) \( 24 x^{2} 2-52 x y+8 y^{2} 2 \) 32) \( 3 x^{2}+13 u y-10 y^{2} \)

Ask by Fernandez Matthews. in the United States
Mar 11,2025

Upstudy AI Solution

Tutor-Verified Answer

Answer

Here are the factorizations for the given expressions: 1. \( 4x^{2} + 13x + 3 = (x + 3)(4x + 1) \) 2. \( 4x^{2} + \pi - 3 \) (No solution found) 3. \( 3x^{2} - 4x - 4 = (x - 2)(3x + 2) \) 4. \( 2x^{2} - 5x - 3 = (x - 3)(2x + 1) \) 5. \( 7a^{2} - 11a + 4 = (a - 1)(7a - 4) \) 6. \( 24x^{2} - 30a + 9 = 3(8x^{2} - 10a + 3) \) 7. \( 2x^{3}y + 12x^{2}y + 18xy = 2xy(x + 3)^2 \) 8. \( 2x^{2} + 8x + 6 = 2(x + 1)(x + 3) \) 9. \( 24x^{2} \times 2 - 52xy + 8y^{2} \times 2 = 4(12x^{2} - 13xy + 4y^{2}) \) 10. \( 3x^{2} + 13uy - 10y^{2} \) (No solution found) If you need more help with any of these, let me know!

Solution

Factor the expression by following steps: - step0: Factor: \(7a^{2}-11a+4\) - step1: Rewrite the expression: \(7a^{2}+\left(-4-7\right)a+4\) - step2: Calculate: \(7a^{2}-4a-7a+4\) - step3: Rewrite the expression: \(a\times 7a-a\times 4-7a+4\) - step4: Factor the expression: \(a\left(7a-4\right)-\left(7a-4\right)\) - step5: Factor the expression: \(\left(a-1\right)\left(7a-4\right)\) Factor the expression \( 2 x^{3} y+12 x^{2} y+18 x y \). Factor the expression by following steps: - step0: Factor: \(2x^{3}y+12x^{2}y+18xy\) - step1: Rewrite the expression: \(2xyx^{2}+2xy\times 6x+2xy\times 9\) - step2: Factor the expression: \(2xy\left(x^{2}+6x+9\right)\) - step3: Factor the expression: \(2xy\left(x+3\right)^{2}\) Factor the expression \( 24 x^{2}-30 a+9 \). Factor the expression by following steps: - step0: Factor: \(24x^{2}-30a+9\) - step1: Factor the expression: \(3\left(8x^{2}-10a+3\right)\) Factor the expression \( 4 x^{2}+13 x+3 \). Factor the expression by following steps: - step0: Factor: \(4x^{2}+13x+3\) - step1: Rewrite the expression: \(4x^{2}+\left(1+12\right)x+3\) - step2: Calculate: \(4x^{2}+x+12x+3\) - step3: Rewrite the expression: \(x\times 4x+x+3\times 4x+3\) - step4: Factor the expression: \(x\left(4x+1\right)+3\left(4x+1\right)\) - step5: Factor the expression: \(\left(x+3\right)\left(4x+1\right)\) Factor the expression \( 3 x^{2}-4 x-4 \). Factor the expression by following steps: - step0: Factor: \(3x^{2}-4x-4\) - step1: Rewrite the expression: \(3x^{2}+\left(2-6\right)x-4\) - step2: Calculate: \(3x^{2}+2x-6x-4\) - step3: Rewrite the expression: \(x\times 3x+x\times 2-2\times 3x-2\times 2\) - step4: Factor the expression: \(x\left(3x+2\right)-2\left(3x+2\right)\) - step5: Factor the expression: \(\left(x-2\right)\left(3x+2\right)\) Factor the expression \( 2 x^{2}+8 x+6 \). Factor the expression by following steps: - step0: Factor: \(2x^{2}+8x+6\) - step1: Rewrite the expression: \(2x^{2}+2\times 4x+2\times 3\) - step2: Factor the expression: \(2\left(x^{2}+4x+3\right)\) - step3: Factor the expression: \(2\left(x+1\right)\left(x+3\right)\) Factor the expression \( 2 x^{2}-5 x-3 \). Factor the expression by following steps: - step0: Factor: \(2x^{2}-5x-3\) - step1: Rewrite the expression: \(2x^{2}+\left(1-6\right)x-3\) - step2: Calculate: \(2x^{2}+x-6x-3\) - step3: Rewrite the expression: \(x\times 2x+x-3\times 2x-3\) - step4: Factor the expression: \(x\left(2x+1\right)-3\left(2x+1\right)\) - step5: Factor the expression: \(\left(x-3\right)\left(2x+1\right)\) Factor the expression \( 24 x^{2} 2-52 x y+8 y^{2} 2 \). Factor the expression by following steps: - step0: Factor: \(24x^{2}\times 2-52xy+8y^{2}\times 2\) - step1: Multiply the terms: \(48x^{2}-52xy+8y^{2}\times 2\) - step2: Multiply the terms: \(48x^{2}-52xy+16y^{2}\) - step3: Factor the expression: \(4\left(12x^{2}-13xy+4y^{2}\right)\) Here are the factorizations for the given expressions: 1. **For \( 4 x^{2}+13 x+3 \)**: - Factorization: \((x+3)(4x+1)\) 2. **For \( 4 x^{2}+\pi-3 \)**: - Result: No result could be found for the input provided. 3. **For \( 3 x^{2}-4 x-4 \)**: - Factorization: \((x-2)(3x+2)\) 4. **For \( 2 x^{2}-5 x-3 \)**: - Factorization: \((x-3)(2x+1)\) 5. **For \( 7 a^{2}-11 a+4 \)**: - Factorization: \((a-1)(7a-4)\) 6. **For \( 24 x^{2}-30 a+9 \)**: - Factorization: \(3(8x^{2}-10a+3)\) 7. **For \( 2 x^{3} y+12 x^{2} y+18 x y \)**: - Factorization: \(2xy(x+3)^{2}\) 8. **For \( 2 x^{2}+8 x+6 \)**: - Factorization: \(2(x+1)(x+3)\) 9. **For \( 24 x^{2} 2-52 x y+8 y^{2} 2 \)**: - Factorization: \(4(12x^{2}-13xy+4y^{2})\) 10. **For \( 3 x^{2}+13 u y-10 y^{2} \)**: - Result: No result could be found for the input provided. If you need further assistance or explanations for any specific expression, feel free to ask!

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Extra Insights

When it comes to expanding and factoring polynomials, it's fascinating to note that many mathematical concepts we use today have roots tracing back centuries! For example, the quadratic formula, essential for solving \( ax^2 + bx + c = 0 \), was known to ancient civilizations like the Babylonians, who had techniques for solving specific quadratic equations. To tackle these polynomial problems effectively, always start by looking for common factors first before attempting to use formulas or the quadratic method. A common mistake is thinking every polynomial can be easily factored into nice, neat parts—sometimes, especially with higher-degree terms or non-integer coefficients, you may need to embrace that some factors will remain quadratic or even irrational numbers!

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