d) If the angles of a triangle are in the ratio \( 2: 3: 5 \), find them. If two acute angles of a right angled triangle are in the ratio \( 1: 2 \), find them. If \( x^{\circ} \) is the exterior angle and \( 70^{\circ} \) and \( 50^{\circ} \) are its opposite interior angle of
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To find the angles in a triangle with a ratio of \(2:3:5\), start by letting the angles be \(2x\), \(3x\), and \(5x\). Since the sum of the angles in a triangle is \(180^\circ\), you’ll set up the equation \(2x + 3x + 5x = 180\). Solving this gives \(10x = 180\), so \(x = 18\). Therefore, the angles are \(36^\circ\) (2: \(2x\)), \(54^\circ\) (3: \(3x\)), and \(90^\circ\) (5: \(5x\)). For the acute angles in a right-angled triangle where the ratios are \(1:2\), let the angles be \(x\) and \(2x\). Since one angle is \(90^\circ\), you have \(x + 2x + 90^\circ = 180^\circ\). This simplifies to \(3x = 90\), giving \(x = 30^\circ\). Hence, the angles are \(30^\circ\) and \(60^\circ\): a perfect pair to sum up the right triangle's requirements!