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Ind the median of the following sets of numbers: \( \begin{array}{l}43 ; 22 ; 8 ; 17 ; 29 ; 11 ; 65 ; 36 ; 10 \\ 3 ; 127 ; 35 ; 16 ; 83 ; 61 ; 16 ; 92 ; 18 ; 24\end{array} \)

Ask by Sullivan Sullivan. in South Africa
Mar 14,2025

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The median of the first set is 22, and the median of the second set is 29.5.

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To find the median, we first need to organize the numbers in each set in ascending order. For the first set: \( \{8, 10, 11, 17, 22, 29, 36, 43, 65\} \) The median is the middle number, so since there are 9 numbers (an odd count), the median is the 5th number: **22**. For the second set: \( \{3, 16, 16, 18, 24, 35, 61, 83, 92, 127\} \) The median is the average of the 5th and 6th numbers, since there are 10 numbers (an even count): \( \frac{24 + 35}{2} = 29.5 \). So, the medians are **22** and **29.5**.

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