Ind the median of the following sets of numbers: $$ \begin{array}{l}43 ; 22 ; 8 ; 17 ; 29 ; 11 ; 65 ; 36 ; 10 \ 3 ; 127 ; 35 ; 16 ; 83 ; 61 ; 16 ; 92 ; 18 ; 24\end{array} $$

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1. For the first set:  
   $$
   43,\; 22,\; 8,\; 17,\; 29,\; 11,\; 65,\; 36,\; 10
   $$

**Step 1:** Sort the numbers in increasing order.  
   Sorted order:  
   $$
   8,\; 10,\; 11,\; 17,\; 22,\; 29,\; 36,\; 43,\; 65
   $$

**Step 2:** Determine the median.  
   Since there are $$9$$ numbers (an odd count), the median is the $$\frac{9+1}{2}=5$$th element.  
   The 5th element is $$22$$.

**Median of the first set:** $$22$$

2. For the second set:  
   $$
   3,\; 127,\; 35,\; 16,\; 83,\; 61,\; 16,\; 92,\; 18,\; 24
   $$

**Step 1:** Sort the numbers in increasing order.  
   Sorted order:  
   $$
   3,\; 16,\; 16,\; 18,\; 24,\; 35,\; 61,\; 83,\; 92,\; 127
   $$

**Step 2:** Determine the median.  
   Since there are $$10$$ numbers (an even count), the median is the average of the $$5$$th and $$6$$th elements.  
   The $$5$$th element is $$24$$ and the $$6$$th element is $$35$$.  
   Calculating the median:  
   $$
   \text{Median} = \frac{24 + 35}{2} = \frac{59}{2} = 29.5
   $$

**Median of the second set:** $$29.5$$
The median of the first set is 22, and the median of the second set is 29.5.

Ind the median of the following sets of numbers: \( \begin{array}{l}43 ; 22 ; 8 ; 17 ; 29 ; 11 ; 65 ; 36 ; 10 \\ 3 ; 127 ; 35 ; 16 ; 83 ; 61 ; 16 ; 92 ; 18 ; 24\end{array} \)

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