similar experiment there is no EtOH available to wash the precipitates. After drying for 30 minutes as usual the calculated percentage yields for both compounds are mo \( 100 \% \). Why?

1. When ethanol (\( \text{EtOH} \)) washing is omitted, impurities (such as residual solvents, inorganic salts, or unreacted starting materials) are not removed from the precipitate. 2. These impurities add extra mass to the dried product. When the mass of the impure product is used to calculate the yield, the additional weight from these impurities can make the yield appear artificially high. 3. The drying process (30 minutes in this case) is insufficient to remove all the volatile impurities. As a result, the calculated yield approaches or even reaches \( 100\% \) because the extra mass from impurities is mistakenly counted as product. 4. Therefore, the nearly \( 100\% \) yield is not indicative of a perfect reaction efficiency but rather an artifact of incomplete purification, where the residual contaminants inflate the measured mass.