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What is the measure of each angle of a regular 17-gon? If necessary, round to the nearest tenth.

Ask by Phillips Barrett. in the United States
Mar 11,2025

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Answer

Each angle of a regular 17-gon measures approximately 158.8 degrees.

Solution

To find the measure of each angle of a regular 17-gon, we can use the formula for the sum of interior angles of a polygon: \[ \text{Sum of interior angles} = (n - 2) \times 180^\circ \] where \( n \) is the number of sides of the polygon. For a regular 17-gon, the number of sides is 17. Plugging this into the formula, we get: \[ \text{Sum of interior angles} = (17 - 2) \times 180^\circ = 15 \times 180^\circ = 2700^\circ \] Since the polygon is regular, all interior angles are equal. To find the measure of each angle, we divide the sum of interior angles by the number of sides: \[ \text{Measure of each angle} = \frac{2700^\circ}{17} \] Let's calculate this value. Calculate the value by following steps: - step0: Calculate: \(\frac{2700}{17}\) The measure of each angle of a regular 17-gon is approximately 158.8 degrees. Rounding to the nearest tenth, the measure of each angle is 158.8 degrees.

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Bonus Knowledge

To find the measure of each interior angle of a regular 17-gon, you can use the formula: \((n-2) \times 180^\circ / n\), where \(n\) is the number of sides. So, for a 17-gon, it's \((17-2) \times 180^\circ / 17\), which simplifies to \(15 \times 180^\circ / 17\), resulting in approximately \(158.8^\circ\) for each angle when rounded to the nearest tenth. Imagine hosting a polygon party! Each of the 17 guests (the vertices) comes with a unique angle of about \(158.8^\circ\) to share. As they mingle and form their relationships, the regularity of their angles ensures that no one feels left out, just like in a perfectly symmetrical dance!

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