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\[ \text { resuelve } y=x^{\wedge} \operatorname{sen}(x) \] Para resolver la ecuación \( y=x^{\sin (x)} \) podemos tomar logaritmos para facilitar la derivación.

Ask by Mullins Collins. in Ecuador
Mar 17,2025

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Para resolver la ecuación \( y = x^{\sin(x)} \), toma el logaritmo natural de ambos lados y luego deriva con respecto a \( x \). La derivada es: \[ \frac{dy}{dx} = x^{\sin(x)} \left( \cos(x) \cdot \ln(x) + \frac{\sin(x)}{x} \right) \]

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The Deep Dive

¡Claro que sí! Al tomar el logaritmo natural de ambos lados, transformamos la expresión original \( y = x^{\sin (x)} \) en \( \ln(y) = \sin(x) \cdot \ln(x) \). Esto nos ayuda a utilizar la regla del producto al derivar, lo que facilita el proceso y permite encontrar la derivada de \( y \) con respecto a \( x \) de manera más sencilla. Recuerda que al derivar \( \ln(y) \), se aplica la regla de la cadena, lo que nos lleva a \( \frac{1}{y} \frac{dy}{dx} = \cos(x) \cdot \ln(x) + \sin(x) \cdot \frac{1}{x} \). Finalmente, multiplicamos ambos lados por \( y \) y sustituimos \( y \) de regreso para obtener la derivada final: \( \frac{dy}{dx} = y \left(\cos(x) \cdot \ln(x) + \frac{\sin(x)}{x}\right) \). ¡Así de fácil!

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