Solve the system by substitution. \[ \begin{array}{r}9 x+3 y=-30 \\ -5 x=y\end{array} \] Answer Attempt out of 2

Let's dive into solving this system using substitution! We have two equations here: 1. \( 9x + 3y = -30 \) 2. \( -5x = y \) First, we can substitute \( y \) from the second equation into the first equation. So, replacing \( y \) with \( -5x \): \[ 9x + 3(-5x) = -30 \] Now, simplifying that: \[ 9x - 15x = -30 \] \[ -6x = -30 \] Next, divide both sides by -6: \[ x = 5 \] Now that we have \( x \), we can find \( y \) using the second equation: \[ y = -5(5) \] \[ y = -25 \] So, the solution to the system is \( x = 5 \) and \( y = -25 \). Let's put this in a nice boxed format: \[ \boxed{(5, -25)} \]