Solve the system by substitution. \[ \begin{array}{r}9 x+3 y=-30 \\ -5 x=y\end{array} \] Answer Attempt out of 2

Solve the system of equations \( 9x+3y=-30;-5x=y \). Solve the system of equations by following steps: - step0: Solve using the substitution method: \(\left\{ \begin{array}{l}9x+3y=-30\\-5x=y\end{array}\right.\) - step1: Rewrite the expression: \(\left\{ \begin{array}{l}9x+3y=-30\\y=-5x\end{array}\right.\) - step2: Substitute the value of \(y:\) \(9x+3\left(-5x\right)=-30\) - step3: Simplify: \(-6x=-30\) - step4: Change the signs: \(6x=30\) - step5: Divide both sides: \(\frac{6x}{6}=\frac{30}{6}\) - step6: Divide the numbers: \(x=5\) - step7: Substitute the value of \(x:\) \(y=-5\times 5\) - step8: Calculate: \(y=-25\) - step9: Calculate: \(\left\{ \begin{array}{l}x=5\\y=-25\end{array}\right.\) - step10: Check the solution: \(\left\{ \begin{array}{l}x=5\\y=-25\end{array}\right.\) - step11: Rewrite: \(\left(x,y\right) = \left(5,-25\right)\) The solution to the system of equations by substitution is \( (x, y) = (5, -25) \).