A certain forest covers an area of \( 3100 \mathrm{~km}^{2} \). Suppose that each year this area decreases by \( 9 \% \). What will the area be after 10 years? Use the calculator provided and round your answer to the nearest square kilometer.
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Bonus Knowledge
To determine the area of the forest after 10 years, you can use the formula for exponential decay: \[ A = A_0(1 - r)^t \] where: - \( A_0 \) is the initial area (\( 3100 \, \text{km}^2 \)), - \( r \) is the rate of decrease (9% or 0.09), - \( t \) is the number of years (10). Plugging in the values: \[ A = 3100(1 - 0.09)^{10} \] \[ A = 3100(0.91)^{10} \] \[ A = 3100(0.42241) \quad \text{(approximately)} \] \[ A \approx 1305.47 \, \text{km}^2 \] Rounding to the nearest square kilometer, the area after 10 years will be approximately \( 1305 \, \text{km}^2 \). So, the area of the forest after 10 years will be about 1305 km².
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