Solve the trigonometric equation for all values \( 0 \leq x<2 \pi \). \[ 2 \cos x=1 \]
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To solve the equation \( 2 \cos x = 1 \), first, we can simplify it by dividing both sides by 2: \[ \cos x = \frac{1}{2} \] Now, we need to find all values of \( x \) in the interval \( [0, 2\pi) \) where the cosine function equals \( \frac{1}{2} \). The cosine function is equal to \( \frac{1}{2} \) at specific standard angles: - \( x = \frac{\pi}{3} \) - \( x = \frac{5\pi}{3} \) Thus, the solutions to the equation \( 2 \cos x = 1 \) for \( 0 \leq x < 2\pi \) are: \[ x = \frac{\pi}{3}, \quad x = \frac{5\pi}{3} \]