Maak steeds een kloppende reactievergelijking door de juiste coëfficiënten in te vullen. a $$ \ldots \mathrm{C}_{8} \mathrm{H}_{18}+\ldots \mathrm{O}_{2} \rightarrow \ldots \mathrm{CO}_{2}+\ldots \mathrm{H}_{2} \mathrm{O} $$ b $$ \ldots \mathrm{C}_{6} \mathrm{H}_{6}+\ldots \mathrm{O}_{2} \rightarrow \ldots \mathrm{CO}_{2}+\ldots \mathrm{H}_{2} \mathrm{O} $$ c $$ \ldots \mathrm{C}_{3} \mathrm{H}_{8} \mathrm{O}+\ldots \mathrm{O}_{2} \rightarrow \ldots \mathrm{CO}_{2}+\ldots \mathrm{H}_{2} \mathrm{O} $$ d $$ \ldots \mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O}_{2}+\ldots \mathrm{O}_{2} \rightarrow \ldots \mathrm{CO}_{2}+\ldots \mathrm{H}_{2} \mathrm{O} $$

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We start with octane (C₈H₁₈). The combustion reaction produces carbon dioxide (CO₂) and water (H₂O).

1. Count the carbon (C) atoms: 8 C in C₈H₁₈ means we need 8 CO₂.
2. Count the hydrogen (H) atoms: 18 H in C₈H₁₈ means we need 9 H₂O.
3. Now, we have: C₈H₁₈ + O₂ → 8 CO₂ + 9 H₂O.
4. Calculate the total O atoms needed: 8 CO₂ contributes 16 O and 9 H₂O contributes 9 O, totaling 25 O.
5. Since O₂ has 2 O atoms, we need 25/2 O₂, which simplifies to 12.5 O₂.

The balanced equation is: C₈H₁₈ + 12.5 O₂ → 8 CO₂ + 9 H₂O.
We start with benzene (C₆H₆).

1. Count the carbon (C) atoms: 6 C in C₆H₆ means we need 6 CO₂.
2. Count the hydrogen (H) atoms: 6 H in C₆H₆ means we need 3 H₂O.
3. Now, we have: C₆H₆ + O₂ → 6 CO₂ + 3 H₂O.
4. Calculate the total O atoms needed: 6 CO₂ contributes 12 O and 3 H₂O contributes 3 O, totaling 15 O.
5. Since O₂ has 2 O atoms, we need 15/2 O₂, which simplifies to 7.5 O₂.

The balanced equation is: C₆H₆ + 7.5 O₂ → 6 CO₂ + 3 H₂O.
We start with propanol (C₃H₈O).

1. Count the carbon (C) atoms: 3 C in C₃H₈O means we need 3 CO₂.
2. Count the hydrogen (H) atoms: 8 H in C₃H₈O means we need 4 H₂O.
3. Now, we have: C₃H₈O + O₂ → 3 CO₂ + 4 H₂O.
4. Calculate the total O atoms needed: 3 CO₂ contributes 6 O and 4 H₂O contributes 4 O, totaling 10 O.
5. We have 1 O from C₃H₈O, so we need 9 O from O₂, which means we need 9/2 O₂.

The balanced equation is: C₃H₈O + 4.5 O₂ → 3 CO₂ + 4 H₂O.
We start with acetic acid (C₃H₆O₂).

1. Count the carbon (C) atoms: 3 C in C₃H₆O₂ means we need 3 CO₂.
2. Count the hydrogen (H) atoms: 6 H in C₃H₆O₂ means we need 3 H₂O.
3. Now, we have: C₃H₆O₂ + O₂ → 3 CO₂ + 3 H₂O.
4. Calculate the total O atoms needed: 3 CO₂ contributes 6 O and 3 H₂O contributes 3 O, totaling 9 O.
5. We have 2 O from C₃H₆O₂, so we need 7 O from O₂, which means we need 7/2 O₂.

The balanced equation is: C₃H₆O₂ + 3.5 O₂ → 3 CO₂ + 3 H₂O.
a) C₈H₁₈ + 12.5 O₂ → 8 CO₂ + 9 H₂O b) C₆H₆ + 7.5 O₂ → 6 CO₂ + 3 H₂O c) C₃H₈O + 4.5 O₂ → 3 CO₂ + 4 H₂O d) C₃H₆O₂ + 3.5 O₂ → 3 CO₂ + 3 H₂O

Maak steeds een kloppende reactievergelijking door de
juiste coëfficiënten in te vullen.
a
b
c
d

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