Move the point and the vertex to graph the function \( f(x)=2(x+1)^{2}+2 \)
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To graph the function \( f(x) = 2(x+1)^2 + 2 \), start by identifying the vertex of the parabola. The vertex is found at the point \( (-1, 2) \) since the function is in vertex form \( a(x-h)^2 + k \), where \( (h, k) \) is the vertex. Next, you can plot additional points by choosing values for \( x \) around the vertex. For example, plug in \( x = -2 \) and \( x = 0 \) to find their corresponding \( f(x) \) values. This gives you points \( (-2, 4) \) and \( (0, 6) \). Draw a smooth curve through these points and the vertex to complete your graph!