33 Find the sum of \( \frac{2}{100}+\frac{20}{100}+\frac{2}{10} \) Shew yeur work. Solution:

To solve the sum \( \frac{2}{100}+\frac{20}{100}+\frac{2}{10} \), let's first convert all fractions to have a common denominator. 1. The first fraction is \( \frac{2}{100} \). 2. The second fraction is also \( \frac{20}{100} \). 3. To convert the third fraction, \( \frac{2}{10} \), to a fraction with a denominator of 100, we multiply the numerator and denominator by 10: \[ \frac{2}{10} = \frac{2 \times 10}{10 \times 10} = \frac{20}{100}. \] Now we have: - \( \frac{2}{100} \) - \( \frac{20}{100} \) - \( \frac{20}{100} \) Now we can sum these fractions: \[ \frac{2}{100} + \frac{20}{100} + \frac{20}{100} = \frac{2 + 20 + 20}{100} = \frac{42}{100}. \] Next, we can simplify \( \frac{42}{100} \) by dividing both the numerator and denominator by their greatest common divisor, which is 2: \[ \frac{42 \div 2}{100 \div 2} = \frac{21}{50}. \] So the final answer is: \[ \frac{21}{50}. \]