Factorise (b) $$ 2(5 x+y)(2 y-x)^{2}-4(6 y-3 x)(x-2 y) $$

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Factor the expression $$ 2(5x+y)(2y-x)^{2}-4(6y-3x)(x-2y) $$.
Factor the expression by following steps:
- step0: Factor:
  $$2\left(5x+yight)\left(2y-xight)^{2}-4\left(6y-3xight)\left(x-2yight)$$
- step1: Multiply the terms:
  $$2\left(2y-xight)^{2}\left(5x+yight)-4\left(6y-3xight)\left(x-2yight)$$
- step2: Rewrite the expression:
  $$2\left(2y-xight)^{2}\left(5x+yight)+2\left(2y-xight)^{2}	imes 6$$
- step3: Factor the expression:
  $$2\left(2y-xight)^{2}\left(5x+y+6ight)$$
The factored form of the expression $$2(5x+y)(2y-x)^{2}-4(6y-3x)(x-2y)$$ is $$2(2y-x)^{2}(5x+y+6)$$.
The factored form is $$2(2y - x)^2(5x + y + 6)$$.

Factorise
(b)

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