Question
An advertising agency increased their fees to an \( \$ 80 \) setup fee plus \( \$ 4 \) for every advertisement. Write a rule for the new fee. Write ordered pairs for the fees for \( 10,20,30 \), and 40 advertisements.
Ask by Kelley Huff. in Brazil
Feb 19,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
A regra para a taxa é \( T = 80 + 4x \), onde \( T \) é o custo total e \( x \) é o número de anúncios. Os pares ordenados são:
- 10 anúncios: (10, 120)
- 20 anúncios: (20, 160)
- 30 anúncios: (30, 200)
- 40 anúncios: (40, 240)
Solution
Seja x o número de anúncios. A regra para a taxa é:
T = 80 + 4x
Onde T representa o custo total.
Agora, os pares ordenados para 10, 20, 30 e 40 anúncios são:
• Para 10 anúncios: (10, 80 + 4×10) = (10, 120)
• Para 20 anúncios: (20, 80 + 4×20) = (20, 160)
• Para 30 anúncios: (30, 80 + 4×30) = (30, 200)
• Para 40 anúncios: (40, 80 + 4×40) = (40, 240)
Answered by UpStudy AI and reviewed by a Professional Tutor
Like
error msg
Explain 
Simplify this solution Mind Expander
To express the new fee structure, we can form a rule: \( F(n) = 80 + 4n \), where \( F \) is the total fee and \( n \) is the number of advertisements. Now, let's calculate the fees for 10, 20, 30, and 40 advertisements: - For 10 advertisements: \( F(10) = 80 + 4(10) = 80 + 40 = 120 \) → (10, 120) - For 20 advertisements: \( F(20) = 80 + 4(20) = 80 + 80 = 160 \) → (20, 160) - For 30 advertisements: \( F(30) = 80 + 4(30) = 80 + 120 = 200 \) → (30, 200) - For 40 advertisements: \( F(40) = 80 + 4(40) = 80 + 160 = 240 \) → (40, 240) The ordered pairs representing the fees are: (10, 120), (20, 160), (30, 200), and (40, 240).
