An advertising agency increased their fees to an \( \$ 80 \) setup fee plus \( \$ 4 \) for every advertisement. Write a rule for the new fee. Write ordered pairs for the fees for \( 10,20,30 \), and 40 advertisements.
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Respondido por UpStudy AI y revisado por un tutor profesional
Mind Expander
To express the new fee structure, we can form a rule: \( F(n) = 80 + 4n \), where \( F \) is the total fee and \( n \) is the number of advertisements. Now, let's calculate the fees for 10, 20, 30, and 40 advertisements: - For 10 advertisements: \( F(10) = 80 + 4(10) = 80 + 40 = 120 \) → (10, 120) - For 20 advertisements: \( F(20) = 80 + 4(20) = 80 + 80 = 160 \) → (20, 160) - For 30 advertisements: \( F(30) = 80 + 4(30) = 80 + 120 = 200 \) → (30, 200) - For 40 advertisements: \( F(40) = 80 + 4(40) = 80 + 160 = 240 \) → (40, 240) The ordered pairs representing the fees are: (10, 120), (20, 160), (30, 200), and (40, 240).
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