Question
On a finance exam, 3 students received an \( A, 9 \) students received a \( B \), and 8 students received a \( C \). If a single student is picked at random, what is the probability that the student did not receive a \( C \) ? - Provide the final answer as a fraction.
Ask by Ramirez Sullivan. in the United States
Feb 25,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
The probability is \( \frac{3}{5} \).
Solution
There are a total of 3 + 9 + 8 = 20 students, and the number of students who did not receive a C is 3 + 9 = 12. The probability that a randomly picked student did not receive a C is 12/20, which simplifies to 3/5.
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Simplify this solution The Deep Dive
To find the probability that a randomly selected student did not receive a \( C \), we need to determine the total number of students and how many of those did not receive a \( C \). Total students = \( 3 \) (A) + \( 9 \) (B) + \( 8 \) (C) = \( 20 \) students. Students who did not receive a \( C \) = \( 3 \) (A) + \( 9 \) (B) = \( 12 \) students. Now, the probability that a student did not receive a \( C \) is calculated as: \[ \text{Probability} = \frac{\text{Number of students who did not receive a } C}{\text{Total number of students}} = \frac{12}{20} = \frac{3}{5}. \] Thus, the final answer is \(\frac{3}{5}\).
