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Pon dos problemas quese resuelua Plantiando la proporion dada en cada coso \( \frac{5}{x}=\frac{3}{48} \) \( \frac{7}{12}=\frac{x}{30} \)

Ask by Bush Ayala. in Colombia
Mar 15,2025

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**Problema 1** \[ \frac{5}{x} = \frac{3}{48} \] \[ x = 80 \] **Problema 2** \[ \frac{7}{12} = \frac{x}{30} \] \[ x = 17.5 \]

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Para resolver el primer problema \(\frac{5}{x}=\frac{3}{48}\), puedes cruzar multiplicando: \(5 \cdot 48 = 3 \cdot x\). Esto te da \(240 = 3x\). Luego, divide ambos lados entre 3 para encontrar \(x\): \(x = \frac{240}{3} = 80\). Para el segundo problema \(\frac{7}{12}=\frac{x}{30}\), también cruzamos: \(7 \cdot 30 = 12 \cdot x\). Esto se traduce a \(210 = 12x\). Al igual que antes, divide ambos lados entre 12 para hallar \(x\): \(x = \frac{210}{12} = 17.5\). ¡Y ahí tienes las soluciones!

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