Multiply by using the Distributive Property. 1. \( (3 x+1)\left(x^{3}+4 x^{2}-7\right) \) \[ (2 x-5)\left(4 x^{2}-3 x+1\right) \] 2.
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To tackle \( (3x+1)(x^3+4x^2-7) \) using the Distributive Property, you'll distribute each term in the first parenthesis across the entire second parenthesis. First, multiply \( 3x \) by all terms in \( (x^3 + 4x^2 - 7) \) which gives you \( 3x^4 + 12x^3 - 21x \). Next, multiply \( 1 \) by all terms in \( (x^3 + 4x^2 - 7) \) resulting in \( x^3 + 4x^2 - 7 \). Finally, combine everything: \( 3x^4 + 13x^3 + 4x^2 - 21x - 7 \). Now let's look at \( (2x-5)(4x^2-3x+1) \). Again, distribute each term in the first expression over the second. Start with \( 2x \), giving \( 8x^3 - 6x^2 + 2x \). Then, distribute \( -5 \) which results in \( -20x^2 + 15x - 5 \). Combine the terms for a final expression of \( 8x^3 - 26x^2 + 17x - 5 \). Happy calculating!