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Mary Invested \( \$ 50,000 \) in a retirement account that is increasing in value by \( 4.5 \% \) each year. She plans to leave the money there until she retires in 30 years. a. What are the Independent Variable (IV) and Dependent Variable (DV) in this situation? Use a smart label, describe each and include units. b. Using your variables from part a, Write a function equation that models the situation. c. How much money will Mary have in the account after 20 years? d. What is the situtational domain and range for this function? Be sure to include units in your answers.

Ask by Mcguire Macdonald. in the United States
Mar 13,2025

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Answer

**a. Variables** - **Independent Variable (IV):** \( t \) – Time in years, starting from when Mary invested \$50,000. Units: Years - **Dependent Variable (DV):** \( A(t) \) – The amount of money in the retirement account at time \( t \). Units: Dollars --- **b. Function Equation** \[ A(t) = 50000 \times (1.045)^t \] --- **c. Amount After 20 Years** Mary will have approximately \$120,580 in her account after 20 years. --- **d. Domain and Range** - **Domain:** \( 0 \leq t \leq 30 \) years - **Range:** \$50,000 ≤ \( A(t) \) ≤ \$120,580

Solution

**a. Independent and Dependent Variables** - **Independent Variable (IV):** Label: \( t \) Description: Time in years since Mary made her investment. Units: Years - **Dependent Variable (DV):** Label: \( A(t) \) Description: The value of the retirement account at time \( t \). Units: Dollars --- **b. Function Equation Modeling the Situation** Mary’s account grows at a rate of \( 4.5\% \) per year. The function that models exponential growth is given by: \[ A(t) = P(1 + r)^t \] Substituting in the values: - \( P = 50000 \) (initial investment) - \( r = 0.045 \) (annual growth rate) The function becomes: \[ A(t) = 50000 \times (1.045)^t \] --- **c. Account Value After 20 Years** We substitute \( t = 20 \) into the function: \[ A(20) = 50000 \times (1.045)^{20} \] Calculating \( (1.045)^{20} \) (using a calculator or logarithmic approximation), we get approximately: \[ (1.045)^{20} \approx 2.4116 \] Thus, the account value after 20 years is: \[ A(20) \approx 50000 \times 2.4116 \approx 120580 \] So, Mary will have approximately \$120,580 in her account after 20 years. --- **d. Situational Domain and Range** - **Domain:** Since \( t \) represents the number of years Mary has her money invested, and she plans to retire after 30 years, the domain is: \[ 0 \leq t \leq 30 \quad \text{(years)} \] - **Range:** The smallest amount in the account is at \( t = 0 \), which is \$50,000, and the largest amount is at \( t = 30 \), calculated by: \[ A(30) = 50000 \times (1.045)^{30} \] Therefore, the range for the account value is: \[ 50000 \leq A(t) \leq 50000 \times (1.045)^{30} \quad \text{(dollars)} \]

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The Deep Dive

Mary’s investment in her retirement account can be understood through the concepts of independent and dependent variables, as well as by analyzing the financial growth over time. Here’s a fun breakdown of the solution! a. In this investment scenario, the Independent Variable (IV) is "time in years (t)," which measures the number of years Mary’s money is invested (in years). The Dependent Variable (DV) is "account balance (A)," representing the value of Mary's investment at any given time (in dollars). b. The function that models the situation, considering the compound growth of the account, is given by the equation: \[ A(t) = 50,000(1 + 0.045)^t \] This shows that the account balance grows each year based on the initial investment and the annual interest rate. c. To find out how much money Mary has in the account after 20 years, substitute \( t = 20 \) into the function: \[ A(20) = 50,000(1 + 0.045)^{20} \approx 50,000 \times 2.406619 \approx 120,331.00 \] So, after 20 years, Mary will have approximately **\$120,331.00** in her account. d. The situational domain for this function is the set of all possible time values pertaining to Mary’s investment: **[0, 30] years** (since she plans to leave the money for a maximum of 30 years). The situational range, based on the values the account can take throughout the period, is **[$50,000, $150,276.22]** dollars, indicating the growth from her initial investment to the projected amount at her retirement after 30 years.

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