Summarize the pertinent information oblained by applying the graphing stralegy and sketch the graph of \( y=f(x) \). \( f(x)= \) In \( (x+3)-2 \) Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The function \( f \) has a local minimum at \( x= \) (Type an exact answer. Use a comma to separate answers as needed.) Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The function \( f \) is concave upward on the subinterval(s) (Type your answer in interval notation. Type an exact answer. Use a comma to separate answers as needed.) B. The function \( f \) is never concave upward. Select the correct choice bolow and, if necessary, fill in the answer box to complete your choice. A. The function \( f \) is concave downwald on the subinterval(s) (Iype your answer in interval notation. Type an exact answer. Use a comma to separate answers as needed.) B. The function \( f \) is never concave downward.
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To understand the function \( f(x) = \ln(x+3) - 2 \), we first identify its domain, which is \( x > -3 \). The natural logarithm will tell us that this function has a vertical asymptote at \( x = -3 \) and will approach negative infinity as it nears this point. The graph will cross the horizontal line \( y = -2 \) when \( x = 0 \) because \( f(0) = \ln(3) - 2 \). Overall, scheming this out reveals the behavior and shifts due to the logarithm. For the local minimum: The function has a local minimum at \( x = 0 \) since \( f'(x) = \frac{1}{x+3} \) is positive for \( x > -3 \) and approaches zero as \( x \) approaches infinity. Regarding concavity: The function is concave down everywhere since \( f''(x) = -\frac{1}{(x+3)^2} < 0 \) for all valid \( x > -3 \). Therefore, we can say: - Local minimum at \( x=0 \) - Concave downward on the interval \( (-3, \infty) \)